Sqrt[4x+8]-Sqrt[3x-2]=2

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Solution for Sqrt[4x+8]-Sqrt[3x-2]=2 equation: 


Simplifying
Sqrt[4x + 8] + -1Sqrt[3x + -2] = 2

Reorder the terms:
qrtS[8 + 4x] + -1Sqrt[3x + -2] = 2
[8 * qrtS + 4x * qrtS] + -1Sqrt[3x + -2] = 2
[8qrtS + 4qrtxS] + -1Sqrt[3x + -2] = 2

Reorder the terms:
8qrtS + 4qrtxS + -1qrtS[-2 + 3x] = 2
8qrtS + 4qrtxS + [-2 * -1qrtS + 3x * -1qrtS] = 2
8qrtS + 4qrtxS + [2qrtS + -3qrtxS] = 2

Reorder the terms:
8qrtS + 2qrtS + 4qrtxS + -3qrtxS = 2

Combine like terms: 8qrtS + 2qrtS = 10qrtS
10qrtS + 4qrtxS + -3qrtxS = 2

Combine like terms: 4qrtxS + -3qrtxS = 1qrtxS
10qrtS + 1qrtxS = 2

Solving
10qrtS + 1qrtxS = 2

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
-2 + 10qrtS + 1qrtxS = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 10qrtS + 1qrtxS = 0

The solution to this equation could not be determined.

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